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-16t^2+23t+7=0
a = -16; b = 23; c = +7;
Δ = b2-4ac
Δ = 232-4·(-16)·7
Δ = 977
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{977}}{2*-16}=\frac{-23-\sqrt{977}}{-32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{977}}{2*-16}=\frac{-23+\sqrt{977}}{-32} $
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